Question

Plz ajutor dau coroana

Answer 1

$a) \: 1 \frac{1}{6} + 2 \frac{3}{8} = > \frac{7(4}{6(4} + \frac{19(3}{8(3} = > \frac{24 + 57}{24} = > \frac{85}{24}$

$numitorul \: comun \: dintre \: 6 \: si \: 8 \: din \: ecuatiile \: \frac{7}{6} + \frac{19}{8} \: este \: 24 \: si \: amplificam \: numitorul \: cat \: si \: numaratorul$

$b) \: \frac{12}{35} \times \frac{21(3}{18(3} = > \frac{12(6}{35} \times \frac{7}{6(6} = > \frac{2}{35(7} \times \frac{7(7}{1} = > \frac{2}{5} \times \frac{1}{1} = > \frac{2}{5}$

==strphcriz09==