Question

Plz dau puncte si coroana

Answer 1

$\displaystyle a)~\frac{2}{5} +\frac{3}{25}=\frac{10+3}{25} =\frac{13}{25} \\ \\ b)~\frac{1}{3} -\frac{1}{6} =\frac{2-1}{6} =\frac{1}{6} \\ \\ c)~\frac{6}{5} :\frac{11}{5} \cdot \frac{22}{9} =\frac{6}{5} \cdot \frac{5}{11} \cdot \frac{22}{9} =\frac{6}{11} \cdot \frac{22}{9} =6 \cdot \frac{2}{9} =\frac{12}{9} =\frac{4}{3} \\ \\ d)~0,(5)+0,(1)=\frac{5}{9} +\frac{1}{9} =\frac{6}{9} =\frac{2}{3}$

$\displaystyle e)~\left(\frac{3}{5}\right)^{35}:\Bigg[\left(\frac{3}{5}  \right)^2\Bigg]^{17}\cdot\left(\frac{3}{5}\right)^2= \left(\frac{3}{5} \right)^{35}:\left(\frac{3}{5} \right)^{34}\cdot \left(\frac{3}{5} \right)^2=\\ \\ =\left(\frac{3}{5} \right)^{35-34}\cdot \left(\frac{3}{5} \right)^2=\left(\frac{3}{5} \right)^1\cdot \left(\frac{3}{5} \right)^2=\left(\frac{3}{5} \right)^{1+2}=\left(\frac{3}{5} \right)^3=\frac{27}{125}$

$\displaystyle f)~(4-0,8):\Bigg\{0,(3)+\Bigg[0,1(27)-\frac{1}{11}\Bigg]\cdot\frac{11}{2} \Bigg\}=\\ \\ = 3,2:\Bigg[\frac{3}{9} +\left(\frac{126}{990} -\frac{1}{11} \right)\cdot \frac{11}{2} \Bigg]=\frac{32}{10} :\Bigg[\frac{3}{9} +\left(\frac{7}{55} -\frac{1}{11} \right)\cdot\frac{11}{2} \Bigg]=\\ \\ =\frac{32}{10} :\left(\frac{3}{9} +\frac{7-5}{55} \cdot \frac{11}{2} \right)=\frac{32}{10} :\left(\frac{3}{9} +\frac{2}{55}\cdot\frac{11}{2}\right)=\frac{32}{10}:\left(\frac{3}{9}+\frac{1}{5}\right)=$

$\displaystyle =\frac{32}{10} :\frac{15+9}{45} =\frac{32}{10} :\frac{24}{45} =\frac{32}{10} \cdot \frac{45}{24} =\frac{1440}{240} =6$