Question

PLZ rapid DAU coroana

Answer 1

 

$\displaystyle\\Ex.4)\\\\\Big(6^{25}-20\cdot6^{23}\Big):\Big(6^1-1^6-6^0-0^6\Big)^2=\\\\=\Big(6^{23+2}-20\cdot6^{23}\Big):\Big(6-1-1-0\Big)^2=\\\\=\Big(6^{23}\cdot6^2-20\cdot6^{23}\Big):\Big(4\Big)^2=\\\\=\Big(6^{23}(36-20)\Big):\Big(4\Big)^2=\\\\=6^{23}\cdot16:16=\boxed{\bf6^{23}}$