Question

plzzzzzzzzz? va roooggggg​

Answer 1

Răspuns:

succes...... ....

Answer 2

∡AOB; ∡BOC-∡adiacente, suplementare

⇒m(∡AOB)+m(∡BOC)=180°

m(∡AOB)=60°⇒m(∡BOC)=180°-60°=120°

[OE-bis ∡BOC⇒m(∡COE)=m(∡BOE)=120°/2=60°

[OD-opusa cu [OB⇒m(∡BOD)=180°

m(∡COD)=180°-m(∡BOC)=180°-120°=60°

m(∡DOF)=90°-60°=30°

m(∡EOF)=m(∡COE)+m(∡COF)=60°+90°=150°