Question

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Answer 1

Răspuns:

Explicație pas cu pas:

Problema 282

$P_{romb} = 4l = > 4 l = 40 \: cm = > l = 10 \: cm \\ A_{romb} = {l}^{2} \cdot \: \sin( \angle{B}) = {(10 \: cm)}^{2} \cdot \: \sin(45 \degree) = 100 \: {cm}^{2} \cdot \frac{ \sqrt{2} }{2} = \frac{100 \sqrt{2} {cm}^{2} }{2} = \boxed{ \bold{50 \sqrt{2} {cm}^{2} }}$

Problema 283

$A_{romb} = \frac{D \cdot \: d}{2} = \frac{35 \: cm \cdot8 \: cm}{2} = \frac{280 \: {cm}^{2} }{2} = \boxed{ \bold{140 \: {cm}^{2} }}$