poate bine ca sa mi le rezolve ?
Răspunsuri la întrebare
Răspuns:
a)
Ba(OH)2 hidroxi de bariu
Fe3(PO4)2 fosfat de fier II
P2O5 pentaoxidul de fosfor
AlCl3 clorura de aluminiu
HI acid iodhidric
Na2CO3 carbonat de sodiu
Zn(NO3)2 azotat de zinc
b)
Ba(OH)2
raport atomic Ba:O:H=1:2:2
Fe3(PO4)2
raport atomic Fe: P:O=3:2:8
P2O5
raport atomic P:O=2:5
AlCl3
raport atomic Al:Cl=1:3
HI
raport atomic H:I=1:1
Na2CO3
raport atomic Na:C:O=2:1:3
Zn(NO3)2
raport atomic Zn:N:O=1:2:6
c) MBa(OH)2=137+2x16+2x1=171g/mol
MFe3(PO4)2=3x56 + 2x31+8x16=358g/mol
MP2O5=2x31+5x16=142g/mol
MAlCl3=27+3x35,5=133,5g/mol
MHI=1+127=128g/mol
MNa2CO3=2x23+12+3x16=106g/mol
MZn(NO3)2=65+2x14+6x16=189g/mol
d)
Ba(OH)2
raport de masa Ba:O:H=137:32:2
Fe3(PO4)2
raport de masa Fe:P:O=168:62:128=84:31:64
P2O5
raport de masa P:O=62:80=31:40
AlCl3
raport de masa Al:Cl=27:106,5
HI
raport de masa H:I=1:127
Na2CO3
raport de masa Na:C:O=46:12:48=16:3:12
Zn(NO3)2
raport de masaZn:N:O=65:28 :96
e) Compozitia procentuala
MBa(OH)2=137+2x16+2x1=171g/mol
171gBa(OH)2.........137gBa..........32gO..........2gH
100g Ba(OH)2........x%Ba............y%O...........z%H
x=100x137/171=calculeaza
y=100x32/171=calculeaza
z=100x2/171=calculeaza
MFe3(PO4)2=3x56 + 2x31+8x16=358g/mol
358gFe3(PO4)2.........168gFe..........28gP..........128gO
100g Fe3(PO4)2........x%Fe............y%P...........z%O
x=100x168/358=calculeaza
y=100x28/358=calculeaza
z=100x128/358=calculeaza
MP2O5=2x31+5x16=142g/mol
142gP2O5..............62gP...........80gO
100gP2O5................x%P...............y%O
x=100x62/142=caluleaza
y=100x80/142=calculeaza
MAlCl3=27+3x35,5=133,5g/mol
133,5gAlCl3...........27gAl...............106,5gCl
100gAlCl3...............x%Al................y%Cl
x=100x27/133,5=calculeaza
y=100x106,5/133,5=calculeaza
MHI=1+127=128g/mol
128gHI................1gH............127gI
100gHI...............x%H.............y%I
x=100x1/128=calculeaza
y=100x127/128=calculeaza
MNa2CO3=2x23+12+3x16=106g/mol
106gNa2CO3..........46gNa.............12gC..........48gO
100gNa2CO3...........x%Na................y%C.............z%O
x=100x46/106=calculeaza
y=100x12/106=calculeaza
z=100x48/106=calculeaza
MZn(NO3)2=65+2x14+6x16=189g/mol
189gZn(NO3)2...........65gZn............28gN............96gO
100Zn(NO3)2...............x%Zn.............y%N.................z%O
x=100x65/189=calculeaza
y=100x28/189=calculeaza
z=100x96/189=calculeaza.
Explicație: