Chimie, întrebare adresată de arademarioandrei, 8 ani în urmă

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Răspuns de mihaiimbrisca
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a)

Ba(OH)2 hidroxi de bariu

Fe3(PO4)2 fosfat de fier II

P2O5 pentaoxidul de fosfor

AlCl3 clorura de aluminiu

HI acid iodhidric

Na2CO3 carbonat de sodiu

Zn(NO3)2 azotat de zinc

b)

Ba(OH)2

raport atomic Ba:O:H=1:2:2

Fe3(PO4)2

raport atomic Fe: P:O=3:2:8

P2O5

raport atomic P:O=2:5

AlCl3

raport atomic Al:Cl=1:3

HI

raport atomic H:I=1:1

Na2CO3

raport atomic Na:C:O=2:1:3

Zn(NO3)2

raport atomic Zn:N:O=1:2:6

c) MBa(OH)2=137+2x16+2x1=171g/mol

MFe3(PO4)2=3x56 + 2x31+8x16=358g/mol

MP2O5=2x31+5x16=142g/mol

MAlCl3=27+3x35,5=133,5g/mol

MHI=1+127=128g/mol

MNa2CO3=2x23+12+3x16=106g/mol

MZn(NO3)2=65+2x14+6x16=189g/mol

d)

Ba(OH)2

raport de masa Ba:O:H=137:32:2

Fe3(PO4)2

raport de masa Fe:P:O=168:62:128=84:31:64

P2O5

raport de masa P:O=62:80=31:40

AlCl3

raport de masa Al:Cl=27:106,5

HI

raport de masa H:I=1:127

Na2CO3

raport de masa Na:C:O=46:12:48=16:3:12

Zn(NO3)2

raport de masaZn:N:O=65:28 :96

e) Compozitia procentuala

MBa(OH)2=137+2x16+2x1=171g/mol

171gBa(OH)2.........137gBa..........32gO..........2gH

100g Ba(OH)2........x%Ba............y%O...........z%H

x=100x137/171=calculeaza

y=100x32/171=calculeaza

z=100x2/171=calculeaza

MFe3(PO4)2=3x56 + 2x31+8x16=358g/mol

358gFe3(PO4)2.........168gFe..........28gP..........128gO

100g Fe3(PO4)2........x%Fe............y%P...........z%O

x=100x168/358=calculeaza

y=100x28/358=calculeaza

z=100x128/358=calculeaza

MP2O5=2x31+5x16=142g/mol

142gP2O5..............62gP...........80gO

100gP2O5................x%P...............y%O

x=100x62/142=caluleaza

y=100x80/142=calculeaza

MAlCl3=27+3x35,5=133,5g/mol

133,5gAlCl3...........27gAl...............106,5gCl

100gAlCl3...............x%Al................y%Cl

x=100x27/133,5=calculeaza

y=100x106,5/133,5=calculeaza

MHI=1+127=128g/mol

128gHI................1gH............127gI

100gHI...............x%H.............y%I

x=100x1/128=calculeaza

y=100x127/128=calculeaza

MNa2CO3=2x23+12+3x16=106g/mol

106gNa2CO3..........46gNa.............12gC..........48gO

100gNa2CO3...........x%Na................y%C.............z%O

x=100x46/106=calculeaza

y=100x12/106=calculeaza

z=100x48/106=calculeaza

MZn(NO3)2=65+2x14+6x16=189g/mol

189gZn(NO3)2...........65gZn............28gN............96gO

100Zn(NO3)2...............x%Zn.............y%N.................z%O

x=100x65/189=calculeaza

y=100x28/189=calculeaza

z=100x96/189=calculeaza.

Explicație:

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