Question

poate cineva sa îmi rezolve ex 1​

Answer 1

$\it a)\ (1+3\cdot3^2\cdot3^4):(3^7+1)=(1+3^{1+2+4}):(1+3^7)=(1+3^7):(1+3^7)=1\\ \\ c) \ (4+2^{192}:2^{188}):5=(4+2^4):5=(4+16):5=20:5=4\\ \\ e)\ 2^2+2^4:2-0^7-1^5=4+16:2-0-1=4+8-1=11$

$\it g)\ (3^0\cdot3\cdot3^5:3^5+3^3):15=(3+27)"15=30:15=2$