Question

Poate cineva sa ma ajute la cele 2 exercitii? ?? Va rog frumos....DAU COROANA

Answer 1

[tex]1)\\a^2-b^2=24\\(a-b)(a+b)=24\\4(a+b)=24\\a+b=6\\ 2)\\\frac{x^2+5x+6}{x^2-9}=\frac{x^2+3x+2x+6}{(x-3)(x+3)}=\frac{x(x+3)+2(x+3)}{(x-3)(x+3)}=\frac{(x+2)(x+3)}{(x-3)(x+3)}=\frac{x+2}{x-3}[/tex]