Pornind de la metan obtineti acid izoftalic
Răspunsuri la întrebare
Răspuns:
1500°C
2CH₄ -----> C₂H₂ + 3H₂↑
600-800°C
3C₂H₂ -------------> C₆H₆
AlCl₃ -HCl
C₆H₆ + CH₃-Cl ------> C₆H₅-CH₃ ( toluen) ( CH₃-Cl <-------- CH₄+Cl₂)
lumina
C₆H₅-CH₃ + 3Cl₂ -------> C₆H₅-CCl₃ + 3HCl
AlCl₃
C₆H₅-CCl₃ + CH₃-Cl -----> CH₃ (in meta) - C₆H₄- CCl₃ ( -CCl₃ e substituent de ordinul II, deci se obtine m-metil-triclorometil-benzen)
+3H₂O
CH₃ (in meta) - C₆H₄- CCl₃ ---------------> CH₃ (in meta)- C₆H₄- COOH + 3HCl
NaOH bazic
V₂O₅
CH₃ (in meta)- C₆H₄- COOH + 3[O] ------> COOH ( in meta) - C₆H₄-COOH +H₂O
COOH ( in meta) - C₆H₄-COOH - acid izoftalic ( acid 1,3- benzendicarboxilic)