Question

Poza in descriere am nevoie urgent !!!

Answer 1

Se da:
M=2kg
α=30°
μ=√3/6
a)N=?N
b)m=3kg; a=?m/s²
c)T=?N
d)m1=?kg

Formule:
a)N=Gy
N=G*cosα
N=Mg*cosα

b)Presupunem ca corpul B se misca in jos, iar corpul A spre dreapta, atunci:
T-Gx-Ffr=Ma
G-T=ma

T=Ma+Gx+Ffr
G-ma=T

T=Ma+G*sinα+uN
T=mg-ma

T=Ma+Mg*sinα+uG*cosα
T=mg-ma

T=Ma+Mg*sinα+uMg*cosα
T=mg-ma

Ma+Mg*sinα+uMg*cosα=mg-ma
Ma+ma=mg-Mg*sinα-uMg*cosα
a(M+m)=g(m-M*sinα-uM*cosα)
a=g(m-M*sinα-uM*cosα)/(M+m)

c)T=mg-ma
T=m(g-a)

d)Gx=Ffr+T

T=G1

G*sinα=uN+G1
Mg*sinα=uMg*cosα+m1g
m1g=Mg*sinα-uMg*cosα
m1=M*sinα-uM*cosα
m1=M(sinα-u*cosα)

Calcule:
a)N=2*10*cos30=10√3N
b)a=10*(3-2*sin30-(√3/6)*2*cos30)/(2+3)=3m/s²
c)T=3*(10-3)=21N
d)m1=2*(sin30-(√3/6)*cos30)=0,5kg