Question

Prima ai a doua problema de la punctul A va rooog

Answer 1

a + b = 7 intregi si 1 / 2 

7 intregi si 1 / 2 = ( 7 x 2 + 1) / 2 = 15 / 2 

3 intregi si 3 / 4 = ( 3 x 4 + 3 ) / 4 = 15 / 4 

a + b = 15 / 2 → suma celor doua numere 

a = 15 / 4  → primul termen 

15 / 5 + b = 15 / 2 

b = 15 / 2 - 15 / 4 = 30 / 4 - 15 / 4 = 15 / 4 → celalalt termen 

a = b = 15 / 4 

Verific:   15 / 4 + 15 / 4 = 30 / 4 = 15 / 2 = 7 intregi si 1 / 2 



Problema 2 

25 intregi si 3 / 5 = ( 25 x 5 + 3) / 5 = 128 / 5 
3 intregi si 3 / 8 = ( 3 x 8 + 3) / 8 = 27 / 8 

a + b = 128 / 5 
a = b + 27 / 8 

b + 27 / 8 + b = 128 / 5 
2 b = 128 / 5 - 27 / 8 = ( 8 x 128) / 40 - ( 5 x 27) / 40 = ( 1 024 - 135 ) / 40 
2 b = 889 / 40 
b = 889 / 40 : 2 = 889 / 40 x 1 / 2 = 889 / 80 = 11 intregi si 9 / 80 

a = 889 / 80 + 27 / 8 = ( 889 + 270 ) / 80 = 1159 / 80 = 14 intregi si 39 / 80 

Answer 2

1. n=7 1/2-3 3/4=15/2-15/4=(30-15)/4=15/4
2. n+(n+3 3/8)=25 3/5,  2n=(125+3)/5-(24+3)/8=128/5+27/8=(1024-135)/40=
889/40,  n=(889/40)/2=889/80=11 9/80