Question

primul ex : (1supra2+ 1supra3)•12 supra5= al 2-lea ex : 1supra12-5supra18+1supra9= ex 3: [0,5+0,(3)]:5supra6= ​

Answer 1

Răspuns:

(1/2+1/3)·12/5=aducem la acelasi numitor comun termenii din paranteza

(3/6+2/6)·12/5=5/6·12/5=2 simplificam mezii cu extremii

_______________

1/12-5/18+1/9=aducem la acelasi numitor comun 36

3/36-10/36+4/36=-3/36=-1/12

_____________

(10/5+1/3):5/6=aducem la acelasi numitor comun termenii din paranteza

(30/15+5/15)·6/5=

35/15·6/5=7/3·6/5=42/15=14/5=2,8

Answer 2

1.

( 1 / 2 + 1 / 3 ) × 12 / 5 =

( 3 / 6 + 2 / 6 ) × 12 / 5 =

5 / 6 × 12 / 5 =

60 / 30 = 2

2.

1 / 12 - 5 / 18 + 1 / 9 =

3 / 36 - 10 / 36 + 4 / 36 =

- 7 / 36 + 4 / 36 =

- 3 / 36 = - 1 / 12

3.

[ 0, 5 + 0, ( 3 ) ] : 5 / 6 =

( 5 / 10 + 3 / 9 ) : 5 / 6 =

( 45 / 90 + 30 / 90 ) : 5 / 6 =

75 / 90 : 5 / 6 =

75 / 90 × 6 / 5 =

450 / 450 = 1