Question

Prin arderea a 560 L dintr-un alcan gazos rezulta 248,62 L CO2, masuratibla 30°C si 10 atm. Identificati hidrocarbura.

Answer 1

-calculez moli alcan, CnH2n+2
n= V/Vm= 560 l/22,4l/mol=25mol-

-deduc moli de Co2 ce rezulta la arderea alcanului

1mol...........................................................n,mol
CnH2n+2  +(3n+1)/2 O2-------------------> nCO2 + (n+1)H2O
25mol.......................................................25n, mol(=25n mol C)

-calculez molii de Co2 cuprinsi in volumul dat, in conditii normale
pV=nRT
10X248,62= nx0,082x(30+273)
n= 100mol CO2=100mol C

deci, 25n=100---> n=4--->butan,C4H10