Question

prin c se rezolva adica cum nu raspunsul dar vreu sa ma invat sa il rezolv

Answer 1

Răspuns:

0

Ordinea operatiilor!

Explicație pas cu pas:

efectuam mai inatai 'ridicarile  la putere" si radicalii

9^(-1) =1/9

3^(-3)=1/3³=1/27

√18=√(9*2)=√9*√2=3√2

efectuam impartirile , reprezentate prin liniile de fractie

(1/9):(1/27) =(1/9) *(27/1) =3

3√2:√2=3

efectuam scaderea

3-3=0

Answer 2

$\it \Big(\dfrac{a}{b}\Big)^{-1}=\dfrac{b}{a}\\ \\ \\ \Big(\dfrac{a}{b}\Big)^{-3}= \Big[\Big(\dfrac{a}{b}\Big)^{-1}\Big]^3=\Big(\dfrac{b}{a}\Big)^3=\dfrac{b^3}{a^3}\\ \\ \\ 9^{-1}=\Big(\dfrac{9}{1}\Big)^{-1}=\dfrac{1}{9}\\ \\ 3^{-3}=\Big[\Big(\dfrac{3}{1}\Big)^{-1}\Big]^3=\Big(\dfrac{1}{3}\Big)^3=\dfrac{1}{27}$

$\it\dfrac{9^{-1}}{3^{-3}}-\dfrac{\sqrt{18}}{\sqrt2}=\dfrac{\dfrac{1}{9}}{\dfrac{1}{27}}-\sqrt{\dfrac{18}{2}}=\dfrac{1}{9}:\dfrac{1}{27}-\sqrt9=\dfrac{1}{9}\cdot\dfrac{27}{1}-3=\dfrac{27}{9}-3=3-3=0$