Question

Prin impartirea unui nr natural n la 38 se obtine restul cu 2 mai mare decat catul. Aflati valorile posibile ale nr. n.

Answer 1

n:38=c  = r
r < 38 ⇒ r=1 , 2 , 3 , 4..........................37
r=c+2
n:38=1 rest 3
n=1x38+3 ⇒ n=41
n:38=2 rest 4
n=2x38+4 ⇒ n=80
n:38=3 rest 5
n=3x38+5 ⇒ n=119
n:38=4 rest 6
n=4x38+6 ⇒  n=158
n:38=5 rest 7
n=5x38+7 ⇒ n=197
n:38=6 rest 8
n=6x38+8 ⇒ n=236
n:38=7 rest 9
n=7x38+9 ⇒ n=275
n:38=8 rest 10
n=8x38+10 ⇒ n=314
n:38=9 rest 11
n=9x38+11 ⇒ n=353
n:38=10 rest 12
n=10x38+12 ⇒ n=392
n:38=11 rest 13
n=11x38+13 ⇒ n=431
n:38=12 rest 14
n=12x38+14 ⇒ n=470
n:38=13 rest 15
n=13x38+15 ⇒ n=509
n:38=14 rest 16
n=14x38+16 ⇒ n=548
n:38=15 rest 17
n=15x38+17 ⇒ n=587
n:38=16 rest 18
n=16x38+18 ⇒ n=626
n:38=17 rest 19 
n=17x38+19 ⇒ n=665
n:38=18 rest 20
n=18x38+20 ⇒ n=704
n:38=19 rest 21 
n=19x38+21 ⇒ n=743
n:38=20 rest 22 
n=20x38+22  ⇒ n=782
n:38=21 rest 23
n=21x38+23 ⇒ n=821
n:38=22 rest 24
n=22x38+24 ⇒ n=860
n:38=23 rest 25
n=23x38+25 ⇒ n=899
n:38=24 rest 26
n=24x38+26 ⇒ n=938
n:38=25 rest 27
n=25x38+27 ⇒ n=977
n:38=26 rest 28
n=26x38+28 ⇒ n=1016
n:38=27 rest 29
n=27x38+29 ⇒ n=1055
n:38=28 rest 30
n=28x38+30 ⇒ n=1094
n:38=29 rest 31 
n=29x38+31 ⇒ n=1133
n:38=30 rest 32 
n=30x38+32 ⇒ n=1172
n:38=31 rest 33
n=31x38+33 ⇒ n=1211
n:38=32 rest 34 
n=32x38+34 ⇒ n=1250
n:38=33 rest 35
n=33x38+35 ⇒ n=1289
n:38=34 rest 36
n=34x38=36 ⇒ n=1328
n:38=35 rest 37
n=35x38+37 ⇒ n=1367