Question

Prin impartirea unui numar natural la un numar de o cifra se obtine catul 101 si restul 7. Afla deimpartitul.

Answer 1

a:b=101 rest7
a=101b+7
b apartine {1,2,3,4,5,6}
b=1,a=101x1+7=101+7=108
b=2,a=101x2+7=202+7=209
b=3,a=101x3+7=303+7=310
b=4,a=101x4+7=404+7=411
b=5,a=101x5+7=505+7=512
b=6,a=101x6+7=606+7=613
a=108,209,310,411,512,613

Answer 2

a:b=101 rest 7
b {1,2,3,4,5,6}
a poate fi:
101x1+7=108
101x2+7=209
101x3+7=310=> a {108,209,310,411,512.613}