Question

prin metoda grafica :
La colindat,Alexandra,Teodor,Andrei au primit in preuna 81 nuci.Alexandra are cu 3 nuci mai mult decat Teodor,iar Teodor are cu 6 nuci mai putin decat Andrei.Cate nuci are fiecare copil?
ATENTIE!
Prin metoda crafica.

Answer 1

Al+T+An=81 nuci
Al=T+3
An=T+6
Al,T,An=? nuci
T=1 segment
AI=1 segment+3   } 81
An=1 segment+6
81-(3+6)=81-9=72
72:3(segmente)=24(T)
AI=24+3  => AI=27
An=24+6  => An=30
Solutia: Alexandra=27 nuci; Teodor=24 nuci; Andrei=30 nuci
Verificam: 27+24+30=81 nuci

Answer 2

X+Y+Z=81 NUCI
X=Y+3
Z=Y+6
81-(3+6)=81-9=72
72:3(segmente)=24(T)
AI=24+3  => AI=27
An=24+6  => An=30
 Alexandra=27 nuci; Teodor=24 nuci; Andrei=30 nuci