Question

Prin metoda mersului invers ,va rog​

Answer 1

Răspuns:

1/3×21,2=1/3×212/10=212/30=106/15=7,0(6)

106/15+1/3=106/15+5/15=121/15=8,0(6) (la destinație a consumat)

121/15+212/10=242/30+636/30=878/30=439/15= 29,2(6)

1/4×439/15=439/60=7,31(6)

439/60+1/4=439/60+15/60=454/60=227/30=7,5(6) ( a doua oprire a consumat)

439/15+227/30=878/30+227/30=1105/30= 221/6= 36,8(3)

1/5×221/6=221/30=7,3(6)

1/5+221/30=6/30+221/30=227/30=7,5(6) (prima oprire a consumat)

221/6+227/30=1105/30+227/30=1332/30=

444/10=222/5=44,4

44,4 l (are rezervorul)