Question

Prin metoda reducerii, va rog !!

Answer 1

(3x-2y-5)/5=(3x-5x+3y)/3
(4x-3y-2)/2=(3y-2x+3y)/3

5(3x-5x+3y)=3(3x-2y-5)
2(3y-2x+3y)=3(4x-3y-2)

-10x+15y=9x-6y-15
12y-4x=12x-9y-6

-19x+21y=-15 l(-1)
-16x+21y=-6
____________
3x        /  =   9   =>x=3

-19x+21y=-15 lx(-16)
-16+21y=-6    lx19
_____________
   /    63y   =    126   =>y=2

Rescrie al doilea sistem, nu inteleg ce e acolo...