Question

Prin reactia apei cu 33,6m cubi acetilena(c.n.)se obtin 60 kg acetaldehida de puritate 88%.Care este randamentul reactiei

Answer 1

n = V/Vm = 33,6/22,4 = 1,5 kmoli C₂H₂

m C₂H₂ = 1,5*26 = 39 kg  (mt)

p=m pur/m impur*100 ⇒ m pur = 60*88/100 = 52,8 kg acetaldehida

26 kg...................................................................................44 kg
HC≡CH + H₂O ⇒ H₂C=CH-OH ----(tautomerie)---> H₃C=CH=O
x kg.....................................................................................52,8 kg

x = 31,2 kg C₂H₂ (mp)

η = mp/mt*100 = 31,2/39*100 = Calculeaza !!