Question

Prisma patrulatera regulata ABCDA'B'C'D' are AB egal cu 5 cm si BD' egal cu 13 radical de 2 cm . Aflati inaltimea , aria laterala , volumul

Answer 1

BD'-diagonala prismei⇒BD'^2=2AB^2+BB'^2
                                       (13√2)^2=2×5^2+BB'^2
                                        338=50+BB'^2
                                         BB'^2=288
                                         BB'=2√71=h(inaltimea)
A laterala=P bazei ×h
A lat.=20×2√71
A lat.=40√71
V=A bazei×h
V=25×2√71
V=50√71
Sper ca te-am ajutat! ^..^