Question

probl 29...................

Answer 1

  0,15 moli

C6H5CH=C(CH3)-C6H5 + 3[O] => C6H5COOH + O=C(CH3)-C6H5

   1

n moli

K2Cr2O7 + 4H2SO4 => K2SO4 + Cr2(SO4)3 + 4H2O + 3[O]

  1

=> n = 1x0,15/1 = 0,15 moli K2Cr2O7

Cm = 1/6 , Cm = niu/Vs

=> Vs = 0,15/0,1667 = 0,9 L => B.