Question

probl. 8!
dau coroana!

Answer 1

x= 9^6:3^10-3^8:3^6=(3^2)^6:3^10-3^2=3^12:3^10-3^2=3^2-3^2=0
y=3^6-3^8:3^2+1-0=3^6-3^6+1=0+1=1
x+y=0+1=1
y-x=1-0=1
x^y=0^1=0
y^x=1^0=1
x•y=0•1=0

Answer 2

   
[tex]x=(9^3)^2:3^{10}-3^{2^3} :3^6=\\\\ =9^{3\times2}:3^{10}-3^{8}:3^6=\\\\ =9^6:3^{10}-3^{8}:3^6=\\\\ =(3^2)^6:3^{10}-3^{8}:3^6=\\\\ =3^{2\times6}:3^{10}-3^{8}:3^6=\\\\ =3^{12}:3^{10}-3^{8}:3^6=\\\\ =3^{12-10}-3^{8-6}=3^2-3^2=9-9=\boxed{0}\\\\\\ y=3^2\times3^4-(3^2)^4:3^2+3^0-0^3=\\\\ =3^{2+4}-3^{2\times4}:3^2+3^0-0^3=\\\\ =3^6-3^8:3^2+3^0-0^3=\\\\ =3^6-3^{8-2}+3^0-0^3=\\\\ =3^6-3^6+3^0-0^3=0+1-0 =\boxed{1}\\\\\\ x+y=0+1=\boxed{1}[/tex]

$x-y = 0-1 = \boxed{-1} \\ x^y = 0^1 = \boxed{0} \\ x \cdot y = 0 \cdot 1 = \boxed{0}$