Question

Problema 1
Va rog frumos!

Answer 1

In triunghiul BAC , m(<A)=90°=>Teorema lui Pitagora:CB^2=AB^2+AC^2=144+256=400=>BC=20 m

P=AB+BC+AC=12+20+16=48 m

In triunghiul BAC , m(<A)=90°=>sin C=AB/BC=12/20=3/5

In triunghiul BAC , m(<A)=90°=>sin B=AC/BC=4/5

Fie MF_|_AB=>MF inaltime in triunghiul ABM

d(M,AB)=MF

In triunghiul MFB,m(<F)=90°=>sin B=MF/MB=>MF=MBsinB=6•4/5=24/5 cm

A_AMB=MF•AB/2=24/5•12/2=144/5=28,8 m^2 suprafata violetelor

A=AB•BC/2=12•16/2=96 m^2

96..........100

28,8......x

x=28,8•100/96=30% violete

NC=BC-MN-BM=20-6-4=10 m

Fie NY_|_AC=>NY inaltime in triunghiul ANC

In triunghiul NYC,m(<Y)=90°=>sinC=NY/NC=>NY=NCsinC=10•3/5=6 m

A_ANC=NY•AC/2=6•16/2=48 m^2 suprafata narciselor

96...............100

48...............y

y=48•100/96=50% narcise

100%-50%-30%=20% zambile