Question

problema 10.7, va rog!!!

Answer 1

CH3-CH=C(CH3)-CH3+ [O] ⇒CH3-COOH + CH3-CO-CH3
CH3-CH=C(CH3)-CH3 + HOH ⇒CH3-CH2-(HO)C(CH3)-CH3  (A)
CH3-CO-CH2-CH3 + H2 ⇒ CH3-CH(OH)-CH2-CH3    (B)
C5H10+Cl2 (-HCl)⇒ C5H9-Cl + HOH ⇒ C5H9-OH  (C = ciclopentanol)
daca D = alcool saturat⇒ CxH(2x+2)O
CxH(2x+2)O +(3x-1)/2 O2 ⇒ xCO2  +        (x+1)H2O
    4,6/M                          8,8/44=0,2        5,4/18 = 0,3
n CO2 = x·nD    0,2 = x·4,6/(14x+18)
14x + 18 = 23x    9x = 18      x = 2      C2H5-OH
E:  CH3-CH=CH2 + [O] + H2O ⇒ CH3-CH(OH)-CH2-OH⇒