Question

problema 11 va rog . ..​

Answer 1

Răspuns:

$\frac{4 \times - 1}{ { \times }^{2} - 1 } = \frac{ \times + 1}{ \times - 1} + \frac{1}{ \times }$

$\frac{4 \times - 1}{ { \times }^{2} - 1 } - \frac{ \times + 1}{ \times - 1} - \frac{1}{ \times \ } = 0$

$\frac{4 \times - 1}{x \times ( \times - 1)} - \frac{ \times + 1}{ \times - 1} - \frac{1}{ \times } = 0$

$\frac{4 \times -1 - x \times ( \times + 1) - ( \times - 1) }{x \times ( \times - 1)} = 0$

$\frac{4 \times - { \times - }^{2} - \times - \times }{x \times ( \times - 1)} = 0$

$\frac{2 \times - { \times }^{2} }{x \times ( \times - 1)} = 0$

$\frac{x \times (2 - \times )}{x \times ( \times - 1)} = 0$

$\frac{2 - \times }{ \times - 1} = 0$

$2 - \times = 0$

$- \times = - 2$

$\times = 2$