Question

Problema 1237, va rog!

Answer 1

transform raportul masic in raport molar, stiind A,C=12g/mol  A,H=1g/mol

n,C:n,H= 83,72/12:16,28/1

            =6,98:16,28

            = 1:2,33

formula moleculara: (CH2,33)n

ro=19,2g/5 l= M/Vm

M= 86g/mol

14,33n=86---> n=6,hexan--raSpuns E

IZOMERII SUNT

CH3-CH(CH3)-CH2-CH2-CH3  2 metil- pentan

CH3-CH2-CH(CH3)-CH2-CH3    3metil-pentan

CH3-CH(CH3)-CH(CH3)-CH3      1,2 dimetil-butan

CH3-C(CH3)2-CH2-CH3              2,2 dimetil-butan

CH3-CH(C2H5)CH2CH3               2 etil-butan