Question

Problema 15 va rog,dau coroana

Answer 1

Răspuns:

tg=cateta opusa/cateta alaturata

tg(c)=$\frac{AB}{AC}$

$\frac{AB}{AC} =\frac{4}{3}$

rezulta AB=$\frac{4AC}{3}$

Aplicam teorema lui pitagora

$BC^{2} =AB^{2} +AC^{2}$

$BC^{2} =\frac{16AC^{2} }{9} +AC^{2}$

aducem la acelasi numitor

9*225=25$AC^{2}$

rezulta AC=9, AB = 12

A=$\frac{C1*C2}{2} =\frac{AB*AC}{2} =\frac{9*12}{2} =54cm^{2}$

P=AB+AC+BC=12+9+15=36cm

Answer 2

Răspuns:

Explicație pas cu pas:

tg C=b/c=4/3

b²+c²=a²=225              16c³/9+c²=225     16c²+9c²=225×9

25c²=225×9      c=√225×9/25=15×3/5=9

b=9×4/3=12

P=a+b+c=15+12+9=36 cm

A=bc/2=12×9/2=54 cm²