Question

Problema 16 si problema 18

Answer 1

16.

Vs = 1000 mL = 1 L iar (ro) p = 0,78 kg/L

=> ms = pxVs = 1 x 0,78 = 0,78 kg

 0,78 kg.......................................... V m3

CH3-CH(OH)-CH3 --H+/toC--> CH3-CH=CH2

 60 kg/kmol.....................................22,4

=> V = 0,78x22,4/60 = 0,2912 m3 propena s-ar fi obtinut daca rand. ar fi fost de 100%, insa in cazul nostru rand. = 70%

=> (eta) n = V.practicx100/V.teoretic

=> V.practic = V.teor.x(eta)n/100 = 0,2912x70/100 = 0,2038 m3 sau 203,84 L propena obtinuta => C.

18.

CnH2n + Br2 = CnH2nBr2

=>

la 100% .............................. 14n (alchena initiala)

la 100+228,57 ................... 14n+160

=> 14nx328,57 = 100(14n+160)

=> n = 5 => C5H10 => D.