Question

problema 17 va rogg frumos e urgent

Answer 1

[tex]Aplicam ~teorema~bisectoarei~in ~\Delta ABD:\\\\ \frac{AB}{AD} = \frac{BE}{ED} = \frac{1}{2} \\\\ BE+ \frac{ED}{ED} = \frac{3}{2}= \frac{BD}{ED}\\\\ \Delta FED \sim \Delta CBD\\\\ \frac{ED}{BD} = \frac{EF}{BC}= \frac{2}{3} \\\\ EF= \frac{2}{3} *12\\\\ \bold{EF=8}[/tex]