Question

Problema 2 va rog. ​

Answer 1

Răspuns:

Explicație pas cu pas:

$a-1 = \frac{10}{b+3} => (a-1)(b+3) = 10\\\\(a-1)(b+3) = 1*10\\a-1 = 1 => a = 2\\b+3 = 10 => b = 7\\(a-1)(b+3) = 2*5\\a-1 = 2 => a = 3\\b+3 = 5 => b = 2$

perechile de numere sunt: (2,7) (3,2)

Answer 2

a - 1 = 10/(b+3)

(a-1)(b+3) = 10

10 = 1×10

a - 1 = 1 => a = 2

b + 3 = 10 => b = 7

10 = 2×5

a - 1 = 2 => a = 3

b + 3 = 5 => b = 2