Question

Problema 2 va rog mult.......

Answer 1

a)m∡A≡m∡A
∡ADE≡∡ACB (acelasi complement, ∡A)
b) din a)
DE/BC=AD/AC
DE/3=2/5
Am folositAC=√(3²+4²)=5
deci DE=3*2/5=6/5=1,2km

c)
Fie x , scurtarea distantei
DE +EC +x=DB +BC (1)
AE=√(AD²-DE²)=√(2²-1,2²)=1,6
EC=AC-1,6=5-1,6=3,4
DE +EC=1,2+3,4=4,6

DB+BC=2+3=5
Atuncirelatia (1) devine:
4,6+x=5
x=5-4,6=0,4km