Question

Problema 22 va rog, imi trebuie pt maine ^^'
Multumesc anticipat!

Answer 1

22. C=md/ms*100 => md=C*ms/100=40*40/100=16g NaOH

MNaOH=40g/mol

n=m/M=16/40=0,4 moli NaOH

MAl=27g/mol

n=m/M=5,4/27=0,2 moli Al

NaOH este in exces => 0,4-0,2=0,2 moli NaOH in exces

2Al + 2NaOH + 2H2O => 2NaAlO2 + 3H2

b) 2 moli Al............................3 moli H2
0,2 moli Al............................x=3*0,2/2=0,3 moli H2

c) 2NaOH + H2SO4 => Na2SO4 + 2H2O

2*40g NaOH......................98g H2SO4
16g NaOH..........................x=19,6g H2SO4

C=md/ms*100=>ms=md*100/C=1960/49=40g sol H2SO4

Nu stiu sigur daca am facut bine.,