Question

Problema 35: Determinati numerele rationale pozitive x y z care sunt direct proportionale cu 5 ,6 si 10 iar 2x + 3y - 2z = 128

Answer 1

2x+3y-2z=128

x/5=y/6=z/10=k

x=5k

y=6k

z=10k

2×5k+3×6k-2×10k=128

10k+18k-20k=128

28k-20k=128

8k=128

k=128:8

k=16

x=5×16

x=80

y=6×16

y=96

z=10×16

z=160