Question

Problema 4 va rog………….

Answer 1

$\cos <BAN=\tfrac{AB}{AN} \\ \implies \cos 30^{\circ}=\tfrac{6}{AN} \implies \tfrac{\sqrt{3}}{2}=\tfrac{6}{AN} \\ \implies AN=4\sqrt{3}\:\: cm \\\\ <MAN=90^{\circ}-60^{\circ}=30^{\circ}\\ \\ \implies A_{ΔMAN}=\dfrac{AM×AN×\sin(30^{\circ})}{2} \\ =\dfrac{(4\sqrt{3})^2×\tfrac{1}{2}}{2}=\dfrac{48×\tfrac{1}{2}}{2}=\dfrac{24}{2}=12\:\: cm^2$

Answer 2

Răspuns:

a ) 12 cm²

Explicație pas cu pas:

ai rezolvarea atasata in poza