Question

Problema 4 va rog ,repede dau coroana!

Answer 1

a)Intr-un triunghi dreptunghic mediana este jumatate din ipotenuza=> AD=BC/2=6cm=DB
b)Din T lui Pitagora AC²=BC²-AB²=144-64=√80=4√5
sin C=AC/BC=4√5/12=√5/3
c)AD⊥BC=> AD-inaltime=> AD=AB·AC/BC=8·4√5/12=32√5/12=8√5/3
Aria ADB=DB·AD/2=(6·8√5/3)/2=8√5 cm²

Answer 2

AD mij lui CB =》DB=6
CB=12

cf.T.P
ADla a 2 a = AB la a 2 a+DBla a 2 a × la a 2 a = ×'
AD'= 8'+6'
AD'=64+36
AD=radical din 100=》AD=10cm