Question

problema 5 de la G2

Answer 1

consideram ca din HNO3 se consuma x moli

C6H5-OH + 3HNO3 -------->  TNF + 3H2O

1mol            3 moli                1 mol   3 moli

x/3 moli      x moli                               x moli

md HNO3=315*80/100= 252 g

m  sol finala de acid =315 -63x + 18x= 315 - 45x

md fin=252-63x

35/100= (252-63x) / (315- 45x )  ==> x=3 moli

deci in reactie se consuma un mol de fenol ( 94g)