Question

Problema 5!!! Rapidddd

Answer 1

a) DC||AB
M€AB =>DC||BM , DC||AM
DM||BC
DC||BM =>DAMC paralelogram=>DM=BM, DC=BM=6
AB=AM+BM
12=AM+6
AM=BM=6=> M mijlocul lui AB

b) construim CM pependicular pe AB
mm T.<30=> MB=BC/2
BC=12
In triunghiul MCB mt.p. CM^2+MB^2=BC^2
CM^2+6^2=12^2
CM^2+36=144
CM=v108
CM=6v3

Aabcd= (B+b)*h/2=(AB*DC)*CM/2=(12+6)*6v3/2=18*3v3=54v3cm
54v3=v8748
90=v8.100
V8748>v8100=> 54v3>90