Chimie, întrebare adresată de Utilizator anonim, 9 ani în urmă

problema 6.15, multumesc!

Anexe:

Răspunsuri la întrebare

Răspuns de moonlight01
1
F.g. hidrocarbura aromatica saturata-> CnH2n-6=14n-6

14n-6=106==>14n=112=>n=8 -> F.m C8H10 -> etilbenzen

C6H6 + CH2=CH2 ---> C8H10

C8H10 ---> C6H5-CH=CH2 (vinilbenzen)

C6H5-CH=CH2 ----> -[-C6H5-CH-CH2-]-n 

b) MC8H8=104kg...........................104kg polimer
  52kg.................................................52kg

MC8H10=106kg..................................104kg C8H8
x=53kg......................................................52kg

78kg C6H6........................................106kg C8H10
x=39kg...................................................53kg

n=mp/mt*100==>mp=n*mt/100=78*39/100=30,42kg

1kg=1000g
30,42kg=30420g

ro=m/V==>V=m/ro=30420g/0,88g/cm3=34568,1818cm3=34,568L C6H6



moonlight01: ai raspuns ?
moonlight01: oops :)
moonlight01: era astfel: n=mp/mt*100==>mt=mp*100/n=52*100/78=66,666kg polimer.. 106kg C8H10........................104kg C8H8.........66,666kg C8H8.............x=66,666*106/104=67,94871kg C8H10.... 78kg C6H6...................106kg C8H10.....67,94871kg..............x=78*67,94871/106=50kg C6H6....1kg=1000g => 50*1000=50000g C6H6 => ro=m/V=>V=m/ro=50000g/0,88g/cm3=56811,181818cm3/1000=56,818181L C6H6...
moonlight01: n=mp/mt*100==>mt=mp*100/n=52*100/78=66,666kg polimer

106kg C8H10............................104kg C8H8
x=66,666*106/104=67,94871kg C8H10......66,666kg C8H8

78kg C6H6......................106kg C8H10
x=78*67,94871/106=50kg C6H6......67,94871kg C8H10

1kg=1000g => 50*1000=50000g C6H6 => ro=m/V=>V=m/ro=50000g/0,88g/cm3=56811,181818cm3/1000=56,818181L C6H6...
Alte întrebări interesante