Question

problema 7.11 va rog :)

Answer 1

NE=5 => CnH2n-8, iar compusul clorurat CnH2n-9Cl
%Cl=m Cl/m compus * 100 => 21.32=35.5/14n+28.5*100=>n=10
FM: C10H11Cl
Prin succesiunea de reactii, se observa ca A este naftalina

b) randament = msa practica/teoretica * 100 => mp=404.21*50/100=384 kg 
128 g naftalina.......132 g tetralina
384 kg naftalina............x
x = 396 kg
randament = mp/mt/100=>mp=396*90/100=356,4 kg
132 g tetralina........166.5 g compus clorurat
356.4 kg tetralina...............y
y = 449.55 kg