Question

problema 7 va roggggggg

Answer 1

fie vasele a,b,c
a+b+c= 66 hl
b= a+15 hl
c=a+b⇒ c=a+a+15=2a+15
inlocuim in prima relatie
a+a+15+2a+15=66
4a+30=66
4a= 66-30
4a=36
a=36÷4
a=9 hl in primul vas
b= 9+15= 24 hl in al doilea vas
c= 2×9+15= 18+15= 33 hl in al treilea vas
verificare: 9+24+33=66

Answer 2

......{ Primul vas|—|=9hl

66hl{ Al 2-lea vas|—|+15hl=24hl

.......{Al treilea|—|—|+15hl=9+9+15
..............…....…………………..=33hl


Egalăm segmentele:
|—|=36hl:4=9hl}
|—|.................}66hl-15hl-15hl=36hl
|—|—|.............}. .