Question

problema aflati nr nat x, y, z stiind ca :x+y=56,y+z=88 si x+z=80

Answer 1

din ultimele doua ii scoatem pe x si y in functie de z si apoi inlocuim in prima 

y+z=88=> y=88-z
x+z=80=> x=80-z

80-z+88-z=56
80+88-56=2z
112=2z
z=56

x+56=80
x=24

y+z=88
y+56=88
y=32