Question

Problema:Al+HCl=AlCl3+H2
Al=1,08g
(H2)-?

Answer 1

$h2 = \frac{1.08 \times 2}{27} = 0.08g$

Answer 2

2×27                            3×2
2Al + 6HCl⇒2AlCl3+3H2
1,08                                xg
MAl=27g
MH2=2g
x=1,08×3×3\2×27=calculeaza