Question

Problemă cls a 8 a. Ajutor​

Answer 1

Răspuns:

A)$\sqrt{27}+\sqrt{12} -\sqrt{75}=3\sqrt{3}+2\sqrt{3} -5\sqrt{3}=0$

B)$2\sqrt{8} +3\sqrt{18} -13\sqrt{2} = 4\sqrt{2} +9\sqrt{2} -13\sqrt{2}=0$

C)$\sqrt{2}(\sqrt{2}+\sqrt{3})-\sqrt{3}(2\sqrt{3} +\sqrt{2})=2+\sqrt{6}-6-\sqrt{6}= -4$

D)$(\sqrt{2}-\sqrt{12})(\sqrt{8}+\sqrt{3})=(\sqrt{2}-2\sqrt{3})(2\sqrt{2}+\sqrt{3})= 4+\sqrt{6} -4\sqrt{6}-6= -2-3\sqrt{6 }$

Explicație pas cu pas:

Pur si simplu scoate de sub radical si redu factorii asemenea