Question

Problema din imagine, macar punctul a)...
OFER MULTE PUNCTE

Answer 1

S(ABCD)=1×1,2=1,2m²
S(DPC)=πr²/2+0,25π/2=1,2+0,125π

Answer 2

aria ferestrei Af

Af = aria ABCD + aria semicercului = ABxBC + π R^2 /2

Af = 1 x 1,2 +π/8

Af = 1,2 + 0,125π

b) aria CMDP = aria tr DCM + aria tr DPC = DC x CB/2 + DC x R/2

aria CMDP = 1 x 1,2/2 + 1 x 0,5/2 = 0,85 = 17/20

c) lungime profil Lp

Lp = πR +  2 x AB + 3 x BC = 0,5π + 5,6 = (5π + 56)/10

daca se considera 3,14 < π < 3,15 luam π max

Lp = (5 x 3,15 + 56)/10 = 7,175m

deci  7,2 m de profil sunt suficienti