Question

Problema din imagine...multumesc

Answer 1

$\log_{2}x+\frac{1}{\log_{2}x} = 2 \\ \\ \text{Notez:}\\ \log_{2}x = t,\,\,t\neq 0\\ \\ t+\frac{1}{t} = 2\Big|\cdot t\Rightarrow t^2+1=2t \Rightarrow t^2-2t+1 = 0\\ \Rightarrow (t-1)^2 = 0 \Rightarrow t = 1 \Rightarrow \log_{2}x = 1 \Rightarrow \boxed{x = 2}$