Question

Problema este anexata.

Answer 1

$\vec{G}+2\vec{F_y}=0 \\\\ F_y=F\sin\alpha, \text{ unde } \alpha = (180 - 120) / 2 = 30^\circ \\\\ mg=2F\sin\alpha\implies m=\dfrac{2F\sin\alpha}{g}\\\\ m=400kg$