Question

Problema este anexată.​

Answer 1

Cv=3R/2

Cp=R+Cv=R+3R/2=5R/2

p₁=3p₀

V₁=V₀

p₂=p₀

V₂=3V₀

p₃=3p₀

V₃=3V₀

transformarea 1-2:p=aV

ΔU₁₂=υCv(T₂-T₁)=3Rυ(T₂-T₁)/2=3(p₂V₂-p₁V₁)/2=3(3p₀V₀-3p₀V₀)=0

L₁₂=(p₁+p₂)(V₂-V₁)/2=(3p₀+p₀)(3V₀-V₀)/2=4p₀*2V₀/2=4p₀V₀

Q₁₂=ΔU₁₂+L₁₂=0+4p₀V₀=4p₀V₀>0

Q₂₃=υCv(T₃-T₂)=3Rυ(T₃-T₂)/2=3(p₃V₃-p₂V₂)/2=3(9p₀V₀-3p₀V₀)/2=3*6p₀V₀/2=3*3p₀V₀=9p₀V₀>0

Q₃₁=υCp(T₁-T₃)=5Rυ(T₁-T₃)/2=5(p₁V₁-p₃V₃)/2=5(3p₀V₀-9p₀V₀)/2=-5*6p₀V₀/2=-5*3p₀V₀=-15p₀V₀<0

Qp=Q₁₂+Q₂₃=4p₀V₀+9p₀V₀=13p₀V₀