Question

Problema incercuita, 8.

Answer 1

Nu pune punctele
a)1,85 g CnH2n
560 cm3=0,68 l H2
1,05.........0,56
CnH2n + H2-->B
x...............22,4
$x = \frac{1.05 \times 22.4}{0.56 } = 42$
12n+2n=42=>14n=42=>n=42/14=>n=3=> formula moleculară C3H6
formula de structură CH2=CH-CH3
b)r=randament
mr=masa de propenă reacționat
mi=masa de propenă introdusă
0,63 g.....................................x
CH2=CH-CH3+H2-->CH3-CH2-CH3
42.......................................44
$r = \frac{mr}{mi} \times 100 \\ mr = \frac{r \times mi}{100} \\ mr = \frac{60 \times 1.05}{100} = 0.63 \: g$

$x = \frac{0.63 \times 44}{42} = 0.66 \: g \: propan$