Question

problema spune: efectuati calculele si prezentati rezultatul sub forma unei fractii ireductibile.
Va rog frumos!D-au coroana!Please

Answer 1

$a) \frac{4x+2}{2x+1}= \frac{2(2x+1)}{2x+1} =2$
$b) \frac{5a+5b}{a+b}= \frac{5(a+b)}{a+b} =a+b$[tex]c) \frac{100a+10b+c}{999} + \frac{100c+10a+b}{999}+ \frac{100b+10c+a}{999}= \frac{111a+111b+111c}{999}= \frac{111(a+b+c)}{999} [/tex]$= \frac{a+b+c}{9}$[tex]